C# Program to Check if a Given Number is Even or Odd

In this article, we’ll explore how to write a C# program to check if a Given Number is Even or Odd.

Prerequisites

Before diving into the code, let’s ensure we clearly understand even and odd numbers.

  • Even Numbers: The numbers divisible by 2 without leaving a remainder are known as Even numbers. For example, 2, 4, 6, 8, and 10 are even numbers because each of them can be divided by 2 without leaving any remainder.
  • Odd Numbers: On the other hand, odd numbers are integers that are not divisible by 2, and they leave a remainder of 1 when divided by 2. Examples of odd numbers include 1, 3, 5, 7, and 9. When you try to divide these numbers by 2, there is always a remainder of 1.

Approach 1: Using Modulo Operator

The modulo operator (%) helps us determine the remainder when dividing one number by another. The number is even if the remainder is zero; otherwise, it’s odd.

using System;

class Program
{
    static void Main()
    {
        // Get user input
        Console.Write("Enter a number: ");
        int num = Convert.ToInt32(Console.ReadLine());

        // Check if the number is even or odd
        if (num % 2 == 0)
        {
            Console.WriteLine($"{num} is an even number.");
        }
        else
        {
            Console.WriteLine($"{num} is an odd number.");
        }
    }
}

Output:

Enter a number: 5
5 is an odd number.

Code Explanation:

  • We use Console.ReadLine() to take user input.
  • The % operator calculates the remainder of the division.
  • The result of num % 2 is checked to determine whether it’s equal to 0 (even) or not (odd).

Approach 2: Bitwise AND Operator

Using bitwise operations is another efficient way to check for even or odd numbers.

using System;

class Program
{
    static void Main()
    {
        // Get user input
        Console.Write("Enter a number: ");
        int num = Convert.ToInt32(Console.ReadLine());

        // Check if the number is even or odd
        if ((num & 1) == 0)
        {
            Console.WriteLine($"{num} is an even number.");
        }
        else
        {
            Console.WriteLine($"{num} is an odd number.");
        }
    }
}

Output:

Enter a number: 2
2 is an even number.

Code Explanation:

  • The bitwise AND operation with 1 (num & 1) isolates the least significant bit.
  • If the result is 0, the number is even.

C# program to print odd and even numbers from 1 to 10

Here is a C# program to print odd and even numbers from 1 to 10.

using System;

class Program
{
    static void Main()
    {
        Console.WriteLine("Even and Odd numbers from 1 to 10:");

        for (int i = 1; i <= 10; i++)
        {
            if (i % 2 == 0)
            {
                Console.WriteLine($"{i} is even, ");
            }
            else
            {
                Console.WriteLine($"{i} is odd, ");
            }
        }
    }
}

Output:

Even and Odd numbers from 1 to 10:
1 is odd, 
2 is even, 
3 is odd, 
4 is even, 
5 is odd, 
6 is even, 
7 is odd, 
8 is even, 
9 is odd, 
10 is even,

Code Explanation:

  • We use a for loop to iterate from 1 to 10.
  • The if statement checks if the current number i is even using the modulo % operator. If true, it prints that the number is even; otherwise, it prints that the number is odd.
  • The Console.Write statement is used to print the result

Conclusion

In this article, we choose the modulo operator and bitwise operations to Check if a Given Number is Even or Odd in C#. Both methods achieve the same goal. 

Feel free to experiment with these approaches and incorporate them into your C# programming. Happy coding!

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Shekh Ali
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