In this article, we’ll explore how to write a **C# program to check if a Given Number is Even or Odd**.

Table of Contents

## Prerequisites

Before diving into the code, let’s ensure we clearly understand even and odd numbers.

**Even Numbers:**Â The numbers divisible by 2 without leaving a remainder are known as Even numbers. For example,**2, 4, 6, 8, and 10 are even numbers**because each of them can be divided by 2 without leaving any remainder.**Odd Numbers:**Â On the other hand, odd numbers are integers that are not divisible by 2, and they leave a remainder of 1 when divided by 2. Examples of**odd numbers include 1, 3, 5, 7, and 9**. When you try to divide these numbers by 2, there is always a remainder of 1.

## Approach 1: Using Modulo Operator

The modulo operator (%) helps us determine the remainder when dividing one number by another. **The number is even if the remainder is zero; otherwise, it’s odd.**

```
using System;
class Program
{
static void Main()
{
// Get user input
Console.Write("Enter a number: ");
int num = Convert.ToInt32(Console.ReadLine());
// Check if the number is even or odd
if (num % 2 == 0)
{
Console.WriteLine($"{num} is an even number.");
}
else
{
Console.WriteLine($"{num} is an odd number.");
}
}
}
```

**Output:**

```
Enter a number: 5
5 is an odd number.
```

**Code Explanation:**

- We use
`Console.ReadLine()`

to take user input. - The
`%`

operator calculates the remainder of the division. - The result of
`num % 2`

is checked to determine whether it’s equal to 0 (even) or not (odd).

## Approach 2: Bitwise AND Operator

Using bitwise operations is another efficient way to check for even or odd numbers.

```
using System;
class Program
{
static void Main()
{
// Get user input
Console.Write("Enter a number: ");
int num = Convert.ToInt32(Console.ReadLine());
// Check if the number is even or odd
if ((num & 1) == 0)
{
Console.WriteLine($"{num} is an even number.");
}
else
{
Console.WriteLine($"{num} is an odd number.");
}
}
}
```

**Output:**

```
Enter a number: 2
2 is an even number.
```

**Code Explanation:**

- The bitwise
`AND`

operation with 1 (`num & 1`

) isolates the least significant bit. - If the result is 0, the number is even.

## C# program to print odd and even numbers from 1 to 10

Here is a C# program to print odd and even numbers from 1 to 10.

```
using System;
class Program
{
static void Main()
{
Console.WriteLine("Even and Odd numbers from 1 to 10:");
for (int i = 1; i <= 10; i++)
{
if (i % 2 == 0)
{
Console.WriteLine($"{i} is even, ");
}
else
{
Console.WriteLine($"{i} is odd, ");
}
}
}
}
```

**Output:**

```
Even and Odd numbers from 1 to 10:
1 is odd,
2 is even,
3 is odd,
4 is even,
5 is odd,
6 is even,
7 is odd,
8 is even,
9 is odd,
10 is even,
```

**Code Explanation:**

- We use a
`for`

loop to iterate from 1 to 10. - The
`if`

statement checks if the current number`i`

is even using the modulo`%`

operator. If true, it prints that the number is even; otherwise, it prints that the number is odd. - The
`Console.Write`

statement is used to print the result

## Conclusion

In this article, we choose the modulo operator and bitwise operations to Check if a Given Number is Even or Odd in C#. Both methods achieve the same goal.

Feel free to experiment with these approaches and incorporate them into your C# programming. Happy coding!

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